Looking at the diagram, since OA and OB are radii of the circle, then OA=OB, therefore this forms an isosceles triangle inside the circle. Also, note that since triangle AOB is isosceles ...

Looking at the diagram above, since OA and OB are radii of the circle, then OA = OB, therefore\(AOB\) forms an isosceles triangle inside the circle. Also, note that since \(\Delta AOB\) is ...